If it's not what You are looking for type in the equation solver your own equation and let us solve it.
11x^2+6x-18=0
a = 11; b = 6; c = -18;
Δ = b2-4ac
Δ = 62-4·11·(-18)
Δ = 828
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{828}=\sqrt{36*23}=\sqrt{36}*\sqrt{23}=6\sqrt{23}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6\sqrt{23}}{2*11}=\frac{-6-6\sqrt{23}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6\sqrt{23}}{2*11}=\frac{-6+6\sqrt{23}}{22} $
| 12.50=3x | | -8-8w=-10 | | 3(2z-10)=-22 | | -5d=-4-4d | | -3-d=-10-4d | | -6x-3=1-x-4x | | (x+5)x3=3x+5 | | 4.95+1.3t=t | | 3(2z-10=-12 | | -9+4q=5q | | 2.01x^2-26.64x+70=0 | | 2(x-3)=180 | | 4x+15x=3x+5 | | -6n+n=-12-n | | 2(t−26)=66 | | -9+4q=5 | | 9t=41t+120 | | 1/5(2(x-1)+8)=x | | 350=4x | | (2n+1)(n-5)=0 | | 8-n=2n-10 | | 3k+6=-1/2 | | (3-z)(3z+2)=0 | | s+19/10=3 | | 2n+27/7n=-41/14 | | -3m=5m-8 | | 79=15^x | | 9x+8x=107 | | 5z-2z(1+3)=12 | | 7(2x-8)=4 | | –4y+16=4 | | 7=-11+3x+15 |